I was working on my new script yesterday and encountered this interesting "feature" of groovy.


def listA = [1, 2, 3]
def listB = listA

listB.remove(1)

show(listA) results in:

[2,3]

So I guess when you set listB to listA, they are both pointing to the same memory location?

Can anyone confirm this is the correct behavoir?

Yes, this is the correct behaviour
But you can do a clone :

Ah nice! Sure beats my hand jammed for loop list copy technique